A couple of days ago we saw a Geekbench result from what should be the Xiaomi Redmi K60 Ultra – this revealed that the phone will be powered by the Dimensity 9200+. Now Xiaomi has given official confirmation of that, along with sharing an AnTuTu score from it and a few more details.
The K60 Ultra – which is expected to go global under the name Xiaomi 13T Pro, by the way – will indeed use the 9200+ chip from MediaTek. And in internal testing it has achieved 1,774,714 points on AnTuTu.
This will make it competitive with the top Snapdragon 8 Gen 2 chips out there (the “for Galaxy” and plus versions), in fact, the score is higher than they typically achieve. The Geekbench 6 score didn’t look that impressive, though, so let’s wait for more detailed results to come out.
The AnTuTu team hasn’t shared the score breakdown yet, but it did post photos from a presentation on the Redmi K60 Ultra.
Based on these slides, the Dimensity won’t be the only chip to see action in the K60 Ultra – there will be a PixelWorks X7 visual processor, running an algorithm that Xiaomi developed in-house.
The X7 has been used in phones like the OnePlus 11, Realme GT2 Explorer Master and the Honor Magic5 Pro, for example. It runs low-latency frame interpolation that can double, triple or even quadruple the frame rate with a latency of under 10ms. It can go up to 180Hz at FHD+ and 144Hz at WQHD+ resolution. You can find more in the press release from PixelWorks. Of course, we're yet to find out what Xiaomi has done with its custom algorithm.
The Redmi K60 Ultra will be unveiled at an upcoming major event that will also feature the Xiaomi Mix Fold 3, Xiaomi Pad 6 Max and the Redmi Pad 2 (which, according to Flipkart, is coming on July 19). The Xiaomi 13T and 13T Pro are expected to be unveiled for the global market on September 1.
Xiaomi though doesn't use this word for their real 'ultra' models. They actually use the English word 'Ultra' in China for the Xiaomi 11 ultra, 12s ultra and 13 ultra. Sure this phone will have top notch performance but if y...
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